出现这种情况是由于你的查询字段中是“备注”类型导致的。select * from table1 where KH_Name in (select name from table2)如上代码中,KH_Name 字段类型为“备注”时就会报标题中提到的错误,将该字段类型换为“文本”即可解决
function Request(strName) { var strHref =document.location.href; var intPos = strHref.indexOf("?"); var strRight = strHref.substr(intPos + 1); var arrTmp = strRight.split("&"); for(var i = 0; i < arrTmp.length; i++) …
ID int PRIMARY KEY IDENTITY(1,1)